b^2-4b+12=-6

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Solution for b^2-4b+12=-6 equation:


Simplifying
b2 + -4b + 12 = -6

Reorder the terms:
12 + -4b + b2 = -6

Solving
12 + -4b + b2 = -6

Solving for variable 'b'.

Reorder the terms:
12 + 6 + -4b + b2 = -6 + 6

Combine like terms: 12 + 6 = 18
18 + -4b + b2 = -6 + 6

Combine like terms: -6 + 6 = 0
18 + -4b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-18' to each side of the equation.
18 + -4b + -18 + b2 = 0 + -18

Reorder the terms:
18 + -18 + -4b + b2 = 0 + -18

Combine like terms: 18 + -18 = 0
0 + -4b + b2 = 0 + -18
-4b + b2 = 0 + -18

Combine like terms: 0 + -18 = -18
-4b + b2 = -18

The b term is -4b.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4b + 4 + b2 = -18 + 4

Reorder the terms:
4 + -4b + b2 = -18 + 4

Combine like terms: -18 + 4 = -14
4 + -4b + b2 = -14

Factor a perfect square on the left side:
(b + -2)(b + -2) = -14

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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